3.1.50 \(\int \frac {1}{x (a+b \text {sech}(c+d \sqrt {x}))^2} \, dx\) [50]

Optimal. Leaf size=23 \[ \text {Int}\left (\frac {1}{x \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2},x\right ) \]

[Out]

Unintegrable(1/x/(a+b*sech(c+d*x^(1/2)))^2,x)

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Rubi [A]
time = 0.02, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {1}{x \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[1/(x*(a + b*Sech[c + d*Sqrt[x]])^2),x]

[Out]

Defer[Int][1/(x*(a + b*Sech[c + d*Sqrt[x]])^2), x]

Rubi steps

\begin {align*} \int \frac {1}{x \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx &=\int \frac {1}{x \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx\\ \end {align*}

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Mathematica [A]
time = 79.81, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[1/(x*(a + b*Sech[c + d*Sqrt[x]])^2),x]

[Out]

Integrate[1/(x*(a + b*Sech[c + d*Sqrt[x]])^2), x]

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Maple [A]
time = 3.30, size = 0, normalized size = 0.00 \[\int \frac {1}{x \left (a +b \,\mathrm {sech}\left (c +d \sqrt {x}\right )\right )^{2}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x/(a+b*sech(c+d*x^(1/2)))^2,x)

[Out]

int(1/x/(a+b*sech(c+d*x^(1/2)))^2,x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(a+b*sech(c+d*x^(1/2)))^2,x, algorithm="maxima")

[Out]

-4*(b^3*sqrt(x)*e^(d*sqrt(x) + c) + a*b^2*sqrt(x))/((a^5*d*e^(2*c) - a^3*b^2*d*e^(2*c))*x*e^(2*d*sqrt(x)) + 2*
(a^4*b*d*e^c - a^2*b^3*d*e^c)*x*e^(d*sqrt(x)) + (a^5*d - a^3*b^2*d)*x) + log(x)/a^2 - integrate(2*(a*b^2*sqrt(
x) + (b^3*sqrt(x)*e^c + (2*a^2*b*d*e^c - b^3*d*e^c)*x)*e^(d*sqrt(x)))/((a^5*d*e^(2*c) - a^3*b^2*d*e^(2*c))*x^2
*e^(2*d*sqrt(x)) + 2*(a^4*b*d*e^c - a^2*b^3*d*e^c)*x^2*e^(d*sqrt(x)) + (a^5*d - a^3*b^2*d)*x^2), x)

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(a+b*sech(c+d*x^(1/2)))^2,x, algorithm="fricas")

[Out]

integral(1/(b^2*x*sech(d*sqrt(x) + c)^2 + 2*a*b*x*sech(d*sqrt(x) + c) + a^2*x), x)

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Sympy [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x \left (a + b \operatorname {sech}{\left (c + d \sqrt {x} \right )}\right )^{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(a+b*sech(c+d*x**(1/2)))**2,x)

[Out]

Integral(1/(x*(a + b*sech(c + d*sqrt(x)))**2), x)

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Giac [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(a+b*sech(c+d*x^(1/2)))^2,x, algorithm="giac")

[Out]

integrate(1/((b*sech(d*sqrt(x) + c) + a)^2*x), x)

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int \frac {1}{x\,{\left (a+\frac {b}{\mathrm {cosh}\left (c+d\,\sqrt {x}\right )}\right )}^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*(a + b/cosh(c + d*x^(1/2)))^2),x)

[Out]

int(1/(x*(a + b/cosh(c + d*x^(1/2)))^2), x)

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